Question

find the domain of the real valued function f(x)=1/log(2-x)​

Answer 1

Answer:

2-x<0 (because negative log is not allowed),

2-x=1(log(1) is equal to 0 hence f(0) becomes infinite which is not allowed)

Hence domain is (-infinity, 2)-{1}

It can have any value except 0

Hence it’s range is (-infinity, 0)U(0,infinity)

hope it helps you

please mark me as brainlist

Answer 2

We have to find domain of the given function :-

$\rm \large f(x) = \dfrac{1}{log (2-x)}$

We know that denominator cannot be zero.

$\rm \longrightarrow log (2-x) \ne0 \\ \\ \rm \longrightarrow (2-x) \ne {e}^{0} \\ \\ \rm \longrightarrow 2-x \ne 1\\ \\ \rm \longrightarrow 2 - 1 \ne x\\ \\ \rm \longrightarrow 1 \ne x\\ \\ \rm \longrightarrow x \ne 1 \: \: \: \: ...(1)$

Also,

$\large \rm \longrightarrow 2 - x > 0 \\ \\ \large \rm \longrightarrow 2 > x \: \: ...(2)$

From equation (1) and (2) :-

$\rm D_f = x \in (- \infty, 2) - \{1 \} \\ or \\ \rm D_f = x \in (- \infty, 1) \cup (1,2) \\ \\ \rm \: where \: D_f \: is \: domain \: of \: the \: function$