Question

Find the domain of the real valued function: f(x) = $\sqrt{4x - x^{2}}$

Answer 1

The $\textbf{domain}$ of function $\textbf{f(x)}$ is the set of all values for which function is defined.

we have to find domain of function : f(x) = $\sqrt{4x-x^2}$

To define f(x),

(4x - x²) ≥ 0 [ as we know, square root is possible only of positive terms ]

x(4 - x) ≥ 0

plot in number line and use inequality concepts ,
we get, 0 ≤ x ≤ 4

hence, domain of function $\in [0,4]$

Answer 2

Answer:

[0, 4]

Step-by-step explanation:

this is the answer