Math, asked by PragyaTbia, 1 year ago

Find the domain of the real valued function: f(x) =  \sqrt{x^{2} - 25}

Answers

Answered by abhi178
1
The \textbf{domain} of function \textbf{f(x)} is the set of all values for which function is defined.

we have to find domain of real valued function : f(x) = \sqrt{x^2-25}

To define f(x),

x² - 25 ≥ 0 [ because we know, square root is possible only of positive terms ]

or, (x - 5)(x + 5) ≥ 0

x ≥ 5 or, x ≤ -5

hence, domain of function \in (-\infty,-5]\cup[5,\infty)
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