Question

find the domain of the √x^2+1+1/√x^2-3x+2​

Answer 1

Step-by-step explanation:

What is the domain of the given function F(x) = sqrt x^2 - 1 + 1/sqrt x^2-3x+2?

F(x)=√(x²-1) +1/√(x²-3x+2)

Since the domain of any function must be in the set of Real numbers. So

x²-1≥0 and x²-3x+2>0

(x+1)(x-1)≥0 and x²-x-2x+2≥0

(x-(-1))(x-1)≥0 and x(x-1)-2(x-1)≥0

(x-(-1))(x-1)≥0 Π (x-1)(x-2)≥0

x€{(-oc,-1]U[1,oc) Π(-oc,1]U[2,oc)

x€(-oc,-1]U[2,oc)

Answer 2

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