Question

find the domain of (x)=1/√2-x^2​

Answer 1

Answer:

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Answer 2

$\huge\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Answer}}}}}}}} \\ \large\pink{\boxed{\blue{\boxed{ \purple{ \boxed{{\pink{Your~answer↓}}}}}}}} \\ \small\bold\red{to \: find \: domain \: of \:f(x) = \frac{1}{\sqrt{2 - {x}^{2} }} } \\ f(x) \: is \: defined \: when \: \\ 2 - {x}^{2} > 0 \\ = > - ( {x}^{2} - 2) > 0 \\ = > {x}^{2} - 2 < 0 \\ = > (x - \sqrt{2} )(x + \sqrt{2} ) < 0 \\ = > - \sqrt{2} < x < \sqrt{2} \\ \large\bold\red{domain \: of \: f(x) \: is \: x∈ ( - \sqrt{2} ,   \sqrt{2} )}$

$\huge \fcolorbox{black}{cyan}{♛Hope it helps U♛}$