Find the domain of x square + 3 x + 5 / x square - 5 x + 4
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Answer:
f (x) = x² + 3x + 5 / x² - 5x + 4
= x² + 3x + 5 / x² - 4x - x + 4
= x² + 3x / x (x-4) - 1 (x-4)
= x² + 3x + 5 / (x - 4) (x - 4)
(x - 4) (x - 1) ≠ 0
x ≠ 4 and x ≠ 1
Domain will be all real numbers except 1 and 4
Domain = R - { 1, 4 }
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Answered by
0
Answer:
f (x) = x² + 3x + 5 / x² - 5x + 4
= x² + 3x + 5 / x² - 4x - x + 4
= x² + 3x / x (x-4) - 1 (x-4)
= x² + 3x + 5 / (x - 4) (x - 4)
(x - 4) (x - 1) ≠ 0
x ≠ 4 and x ≠ 1
Domain will be all real numbers except 1 and 4
Domain = R - { 1, 4 }
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