Math, asked by Nilesh4633, 1 year ago

Find the domain of x square + 3 x + 5 / x square - 5 x + 4

Answers

Answered by Anonymous
4

Answer:

f (x) = x² + 3x + 5 / x² - 5x + 4

= x² + 3x + 5 / x² - 4x - x + 4

= x² + 3x / x (x-4) - 1 (x-4)

= x² + 3x + 5 / (x - 4) (x - 4)

(x - 4) (x - 1) ≠ 0

x ≠ 4 and x ≠ 1

Domain will be all real numbers except 1 and 4

Domain = R - { 1, 4 }

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Step-by-step explanation:

Answered by Anonymous
0

Answer:

f (x) = x² + 3x + 5 / x² - 5x + 4

= x² + 3x + 5 / x² - 4x - x + 4

= x² + 3x / x (x-4) - 1 (x-4)

= x² + 3x + 5 / (x - 4) (x - 4)

(x - 4) (x - 1) ≠ 0

x ≠ 4 and x ≠ 1

Domain will be all real numbers except 1 and 4

Domain = R - { 1, 4 }

@#opeless

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