find the domen and range of the function f(x)= 2√(4 - x^2 ) - 3
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f(x) = √(4x - x^2) = a Domains: - 4x - x^2< 0 x(4 - x)< xepsilon[0,4] x^2 - 4x + a^2 = 0[a>0] x = 4±√(16 - 4a^2)2 = 1±√(1 - a^2) 4 - a^2<0 aepsilon[0,2] ...
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