Find the dot product u.v and ‖u‖,‖v‖ of the vectors u= (2−i,3), v= (i,3 + 4i).
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u.v = (2-i)i + 3(3+4i)
= 2i +1 + 9 +12i
= 10+14i
mod U = √4 -1 - 4i + 9 = √12+4i
mod v = √-1 + 9-16 +24i = √-8+24i
= 2i +1 + 9 +12i
= 10+14i
mod U = √4 -1 - 4i + 9 = √12+4i
mod v = √-1 + 9-16 +24i = √-8+24i
sra3844:
how we get 1 in this step ( 2i +1 + 9 +12i) ..???
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