find the double derivatives of (cosx)^2
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1
Answer:
-2cos2x
Step-by-step explanation:
Please find the attached file.
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anjum187:
thanq very much
I also want double derivative of xsinx
Please find the attached file.
found it thanks
Welcome (^_^)
Answered by
0
d/dx (cosx)^2=2 cos x (-sinx)
on differentiating it again:-
= 2 (cosx . -cosx) + 2 (-sinx.-sinx)
= -2 cos^2 x + 2 sin^2 x
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