Find the dremainder when
F(x) = 12003 - 1302
12003 - 13 002 - 5047 is divided by
(32C+2)?
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Answer:
f(x)=12x3−13x2−5x+7
3x+2=0
x=−23
now as f(x)=p(g(x))+R
f(−23)=p(g(−23))+R
f(−23)=R
R=12(−23)3−13(−23)2−5(−23)+7
=12⋅(−827)−13⋅49+103+7
=−329−529+103+7
=−32−52+30+639
=−84+939
=99=1 remainder
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