Question

Find the drift velocity of copper wire whose cross sectional area is 1 mm2

.

When the wire carries a current of 10 A. Assume that each copper atom

contribute one electron to the electron gas. (Given n-= 8.5 x 1028 m3

)​

Answer 1

Given:

Current, I = 10A

Area, A = $1mm^{2} = 10^{-6}m^{2}$

n = $8.5\times 10^{28} m^{3}$

Charge, e = $1.6\times 10^{-19}C$

Find: We have to calculate the drift velocity

Step by Step Solution: We know the expression to calculate the drift velocity in terms of area, current and n.

So, the expression is,

$v_{d} = \dfrac{I}{neA}$

$v_{d} = \dfrac{10}{8.5\times 10^{28} \times 1.6 \times 10^{-19} \times 10^{-6} }\\\\v_{d} = 735.2941 m/s$

so, the drift velocity is 735.2941 m/s