Question

Find the dy/dx for thisX²+y²+4x+6y+1=0?

Answer 1

Answer:

dy/dx=(-(x+2)/(y+3))

Step-by-step explanation:

differentiating both sides

2x+2y*y'+4+6y'=0

=>  -(2x+4)=2yy'+6y'

-(2x+4)=y'*(2y+6)

so y'=dy/dx=-(2x+4)/(2y+6)

simplyfying

dy/dx=(-(x+2)/(y+3))