Question

find the dy/dx if y=log(1+sinx)​

Answer 1

Answer

dy/dx=cosx/1+sinx

Step-by-step explanation:

y=log(1+sinx)

dy/dx=1/1+sinx · d/dx(1+sinx)

dy/dx=1/1+sinx·(0+cosx)

dy/dx=cosx/1+sinx.

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