Math, asked by jaydakdemyztik, 17 hours ago

Find the Dy/dx of the function, 2y^2 = 2x^2y + 3xy^3

Answers

Answered by devilgod402

0

Step-by-step explanation:

4ydy=2x^2dy+4ydx+3x×3y^2dy+3y^3dx

Dy(4y-2x^2+9xy^2)=dx(4y+3y^3)

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