Question

find the dy/dx of x^x - 2^sinx​

Answer 1

do like this

Step-by-step explanation:

\begin{gathered}y = {x}^{2} - {2}^{sinx} \\ \frac{dy}{DX} = 2x - {2}^{sinx} log(2) \times cosx\end{gathered}

y=x

2

−2

sinxp

DX

dy

=2x−2

sinx

log(2)×cosx