find the DY over DX of the followingY is equal to 3 x minus 2divided by 5 x + 3
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Answer:
Y=(3x-2)÷(5x+3)
(U÷V)'= (VU'-UV')÷V² ( ' means dy/dx)
here U= 3x-1, V= 5x+3, then
U'= 3, V'= 5
put the values, we have
DY/DX= ((5x+3)(3)-(3x-2)(5))÷(5x+3)²
As we know that (a+b)²=a²+2ab+b²
DY/DX= (15x+9-15x+10)÷(25x²+30x+9)
=(19)÷(25x²+30x+9)
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