Question

Find the eaquation of tangent to the curve y=root 3x-2 which is paralle to the line 4x-2y+5 = 0. also write the equation normal to the curve at the point of contact

Answer 1

Answer:

if we differentiate the equation of curve we get slope of tangent at (x,y)

y

!

=

2

(

3x−2)

3

but tangent is parallel to line 4x-2y+5=0

there fore slope is 2

that is

2

(

3x−2)

3

=2

x=

48

41

therefore y=

4

3

equation of tangent is (y−

4

3

)=2(x−

48

41

)

48x−24y−23=0