find the eccentricity of an ellipse whose latus rectum is quarter of its major axis?
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Given: Latus rectum is quarter of its major axis.
To find: The eccentricity of an ellipse.
Solution:
- Let the equation of ellipse be x²/a² + y²/b² = 1 where a>b.
- If eccentricity is e, then it would be:
b² = a²(1-e²) .................(i)
- Now the major axis is 2a.
- Length of latus rectum is 2b²/a²
- Now we have given that:
length of LR = 1/4 x Length of major axis.
2b²/a² = 1/4 x a
2( a²(1-e²)) /a = 1/4 x a ................from (i)
(1-e²)= 1/8
1 - 1/8 = e²
7/8 = e²
e = √7/8
Answer:
So the eccentricity of an ellipse is √7/8
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