Question

Find the eccentricity of the ellipse whose equation is

equation is in attachment

pls give relevant answer​

Answer 1

Length of major axis is 2a

GIVEN:

|z - 4| + |z - 12/5| = 10

SP+S'P =2a

2a=10

a= 5

➵S(4,0) i.e (X1,Y1)

➵S(12/5,0) i.e (X2,Y2)

➵SS'=2ae

➵4-12=2×5×e

5

➵20-12 =10e

5

➵ 8. =e

5×10

➵ 8. =e

50

➵ 4. =e

25

Hope you understand

Answer 2

Question:-

$\sf |z - 4| + |z - \frac{12}{5} | = 10$

Given:-

$\sf |z - 4| + |z - \frac{12}{5} | = 10$

To Find:-

• Eccentricity of the ellipse.

Solution:-

• Length of major axis is 20.

• SP + S'P = 2a

$\sf S = (40),S' = ( \frac{12}{5} ,0)$

2a = 10

a = 5

SS' = 2ae

$\sf\sqrt{(4 - \frac{12}{5} ) {}^{2} + (0 - 0) {}^{2} } = 2(5)e$

$\sf \sqrt{ (\frac{20 - 12 }{5}) {}^{2} } = 10e$

$\sf( \frac{8}{5} ) = 10e$

$\sf \frac{8}{5} \times \frac{1}{10} = e$

$\sf \frac{4}{25} = e$

Answer:-

$\sf \green{ Hence, Eccentricity \: of \: the \: e llipse = \frac{4}{25} }$

[Refer Above attachment]

Hope you have satisfied. ⚘