Question

Find the ecentricity, foci and the length of the latusrectum of the ellipse x²+4y²+8y–2x+1 = 0.

plz ans it if someone know..with explanation​

Answer 1

Answer:

Find eccentricity, foci & length of latus - rectum 

of ellipse

∴x2+4y2+8y−2x+1=0

∴x2−2x+1+4y2+8y+2−1=0

(x−1)2+(2y+2)2−2=0

∴(x−1)2+(2y+2)2=2

∴2(x−1)2+(2)22(y+1)2=1

∴2(x−1)2+1/2(y+1)2=1

→x1=1 & y1=−1

Also,a=2 &b=21

centre =(1,

Answer 2

Answer:

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