Question

Find the effective area of the half-wave dipole antenna operating at 500 mhz

Answer 1

Answer  : given that,

Frequency f = 500 mhz

We know that, the directivity of the half wave dipole antenna is 1.64

The effective area of an antenna is given by

$A_{e} = \dfrac{\lambda^{2}}{4\pi}D$

Now, the wave length is

$\lambda =\dfrac{c}{f}$

$\lambda =\dfrac{3\times10^{8}}{500\times10^{6}}$

$\lambda = 0.6 m$

Now, the effective area

$A_{e} = \dfrac{\lambda^{2}}{4\pi}D$

put the value in the formula

$A_{e} = \dfrac{(0.6)^{2}}{4\pi }\times1.64$

$A_{e} = 0.047\ m^{2}$

Hence, the effective area of the half wave dipole antenna is $0.047^{2}$