Question

Find the effective capacitance of the capacitor given in the network above

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Answer 1

Answer:

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Answer 2

The effective capacitance of the given network of capacitors is 0.9931 μF.

Given,

The capacitance of capacitors,

C1 = 4 μF

C2 = 12 μF

C3 = 3 μF

C4 = 6 μF

C5 = 6/5 μF

To Find,

The effective capacitance of the given network of capacitors

Solution,

This problem can be solved using a simple method.

Capacitor: In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component.

Capacitance: The ratio of the quantity of electric charge held on a conductor to an electric potential difference is known as capacitance.

In the given system, capacitors C1 and C2 are in parallel. Let the effective capacitance of C1 and C2 be C6.

⇒ C6 = 4 μF + 12 μF

⇒ C6 = 16 μF

Also in the given system, capacitors C3 and C4 are in parallel. Let the effective capacitance of C3 and C4 be C7.

⇒ C7 = 3 μF + 6 μF

⇒ C7 = 9 μF

Now, the capacitance C5, C6, and C7 are in parallel. Let the effective capacitance be C.

⇒ 1/C = 1/C5 + 1/C6 + 1/C7

⇒ 1/C = 1/(6/5) + 1/16 + 1/9

⇒ 1/C = 5/6 + 9/144 + 16/144

⇒ 1/C = 120/144 + 25/144

⇒ 1/C = 145/144

⇒ C = 0.9931 μF

Hence, effective capacitance of the given network of capacitors is 0.9931 μF.

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