Question

Find the effective resistance between A and B







Please answer urgently
One who will answer in 5 min, will mark him the brainliest

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{R_{effective_{1}}=\frac{40}{3}\Omega}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies R_{1} = R_{2} = R_{3} = R_{4} = 10\Omega \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies R_{effective} = ?$

• According to given question :

$\bold{For \: parallel \: resistance : } \\ \tt: \implies \frac{1}{ R_{effective_{1}} } = \frac{1}{ R_{2}} + \frac{1}{R_{3} } + \frac{1}{ R_{4} } \\ \\ \tt: \implies \frac{1}{ R_{effective_{1}} } = \frac{1}{10} + \frac{1}{10} + \frac{1}{10} \\ \\ \tt: \implies \frac{1}{ R_{effective_{1}} } = \frac{1 + 1 + 1}{10} \\ \\ \tt: \implies \frac{1}{ R_{effective_{1}}} = \frac{3}{10} \\ \\ \tt: \implies R_{effective_{1}} = \frac{10}{3}\Omega \\ \\ \bold{For \: series\:combination : } \\ \tt: \implies R_{effective_{2} } = R_{1} + R_{effective_{1} } \\ \\ \tt: \implies R_{effective_{2} } =10 + \frac{10}{3} \\ \\ \tt: \implies R_{effective_{2} } = \frac{30 + 10}{3} \\ \\ \green{\tt: \implies R_{effective_{2} } = \frac{40}{3}\Omega}$

Answer 2

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$\tt{\huge{\purple{ ................... }}}$

QUESTION -

Find the effective resistance between A and B.

SOLUTION -

See the attachment for the Solution ...