Find the effective resistance of the combination of two resistors 15 ohms and 25 ohms connected in parallel.
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Answer. Connected in series = 25+30 =40 ...and then arranged in parallel with 40 ohms....so 1/R= 1/40+1/40=2/40.....so, R=40/2 = 20 ohms is the effective resistance of the combination.
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Answer:
Connected in series = 25+30 =40 ...and then arranged in parallel with 40 ohms....so 1/R= 1/40+1/40=2/40.....so, R=40/2 = 20 ohms is the effective resistance of the combination
Explanation:
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