Question

Find the effective resistance of the following and also find the current drawn from the battery: ​

Answer 1

Answer:

4Ω

Explanation:

let us find effective R of R1 and R2

Rz= R1+R2

   = 4+2

   = 6Ω

Now Rz is parallel to R3

1/Rc = 1/Rz + 1/R3

      = 1/6+ 1/3

1/Rc = 1/2

Rc = 2Ω

Now effective R of fig. is

Rs = Rc+ R4

    = 2+ 2

    = 4Ω