Question

find the effective resistance of the parallel combination of three resistor of resistance 20 40 50 ohm​

Answer 1

Answer:

Equivalent Resistance in Parallel=

\begin{gathered}\frac{a \times b}{a + b} \\ = \frac{20 \times 20}{20 + 20} \\ = \frac{400}{40} \\ = 10\end{gathered}

a+b

a×b

=

20+20

20×20

=

40

400

=10

This is connected to another 10 Ohm Resistor in Series, So net Resistance

= 10 + 10 = 20 \: ohm=10+10=20ohm