Find the effective resistance of the parellel combination
of three resistors of resistance 20ohm, 40ohm ,& 50ohm
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Answer:
Equivalent Resistance in Parallel=
\begin{gathered}\frac{a \times b}{a + b} \\ = \frac{20 \times 20}{20 + 20} \\ = \frac{400}{40} \\ = 10\end{gathered}a+b
a×b
=
20+20
20×20
=
40
400
=10
This is connected to another 10 Ohm Resistor in Series, So net Resistance
= 10 + 10 = 20 \: ohm=10+10=20ohm.
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