Question

find the effective value of g due to height ​

Answer 1

Answer:

a = G*M/R², where a is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance, which, at sea level, the average radius of the Earth is 6.376 * 10^6 m.

For a height h, the acceleration due to gravity is: a = GM/(R+h)^2 … so it decreases as h grows.

Explanation:

What you need to notice about these equations

-The strength of Earth’s gravitational field on a body gets weaker as you move farther away from the Earth’s center. Gravity is considered a weak force.

-Because of the magnitude (10^6) of these variables, h makes little difference until it too, is a sizable number.  

Thank you !

Answer 2

M = Mass of earth

m = mass of body above the earth

G = Universal Gravitational Constant

R = Radius of earth

h = Height of mass 'm' from the surface of the earth

g = Acceleration due to gravity

gh = Acceleration due to gravity at height 'h'

g = GM / R²

gh = GM / (R + h)²

∴ gh/g = [ GM / (R + h)² ] x [ R² / GM ]

∴ gh = g ( R / R + h )²