find the efficiency of a heat engine if the temperature of the source is 108° and sink is 27°C
Answers
Answered by
1
Answer:
efficiency n=1-T2/T1
take temp in kelvin
T1=108+273=381
T2=27+273=300
1‐300/381
81/381
efficiency =0.212
=21.2%
Please mark me as a brainliest
Answered by
2
Answer:
The efficiency of heat engine will be:
Tsink/Tsource
=(273+27)/(273+108)
=300/381
=0.787
So, efficiency will be 0.787
Similar questions