Physics, asked by padmajavalluri123, 3 months ago

find the efficiency of a heat engine if the temperature of the source is 108° and sink is 27°C

Answers

Answered by avani1511vyas

Answer:

efficiency n=1-T2/T1

take temp in kelvin

T1=108+273=381

T2=27+273=300

1‐300/381

81/381

efficiency =0.212

=21.2%

Please mark me as a brainliest

Answered by mathdude500

Answer:

The efficiency of heat engine will be:

Tsink/Tsource

=(273+27)/(273+108)

=300/381

=0.787

So, efficiency will be 0.787

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