Math, asked by hemayadlapalli187, 5 months ago

Find the eg of a circle which passes through (4.1) (6,5)
and having the centre on 4x + 3y - 24 = 0.​

Answers

Answered by pops1202
0

Answer:

x²-6x+y²-8y+15 = 0

Step-by-step explanation:

equation of circle is

(x-h)² + (y-k)² = r², (h,k) is center of circle and r radius

since the circle passes through (4, 1) and (6,5)

(4-h)² + (1-k)² = r² -------(1)

(6-h)² + (5-k)² = r² ------(2)

equting (1) and (2)

we get, h=3, k=4

center is (3,4)

radius is distance between center and any point on circle,

sqrt ((3-6)²+(4-5)²) = √10

substitute the values in circle equation,

(x-3)²+ (y-4)² = (√10)²

=> x²-6x+y²-8y+15 = 0

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