Find the eg of a circle which passes through (4.1) (6,5)
and having the centre on 4x + 3y - 24 = 0.
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Answer:
x²-6x+y²-8y+15 = 0
Step-by-step explanation:
equation of circle is
(x-h)² + (y-k)² = r², (h,k) is center of circle and r radius
since the circle passes through (4, 1) and (6,5)
(4-h)² + (1-k)² = r² -------(1)
(6-h)² + (5-k)² = r² ------(2)
equting (1) and (2)
we get, h=3, k=4
center is (3,4)
radius is distance between center and any point on circle,
sqrt ((3-6)²+(4-5)²) = √10
substitute the values in circle equation,
(x-3)²+ (y-4)² = (√10)²
=> x²-6x+y²-8y+15 = 0
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