Find the eigenvalues and eigenvectors for trigonometric functions
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Problem statement:
Diagonalize the following matrix:
(cosθsinθsinθ−cosθ)(cosθsinθsinθ−cosθ)
My attempt:
Ie found that the eigenvalues of this matrix are λ=−1λ=−1 or λ=1λ=1, so I plugged in λ=−1λ=−1:
(cosθ+1sinθsinθ−cosθ+1)(xy)=0(cosθ+1sinθsinθ−cosθ+1)(xy)=0
I tried to solve this, but I got 2xsinθ=02xsinθ=0. How do I find the eigenvectors?
Diagonalize the following matrix:
(cosθsinθsinθ−cosθ)(cosθsinθsinθ−cosθ)
My attempt:
Ie found that the eigenvalues of this matrix are λ=−1λ=−1 or λ=1λ=1, so I plugged in λ=−1λ=−1:
(cosθ+1sinθsinθ−cosθ+1)(xy)=0(cosθ+1sinθsinθ−cosθ+1)(xy)=0
I tried to solve this, but I got 2xsinθ=02xsinθ=0. How do I find the eigenvectors?
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