Question

Find the electric field at a point P on the perpendicular bisector of a uniformly charged rod. The length of the rod is L, the charge on it is Q and the distance of P from the centre of the rod is a.​

Answer 1

ANSWER

Let λ is the charge density

say λ=LQ

So,

dEP=dEcosθ

dEP=(y2+x2)Kdqcosθ

EP=∫−2L2LL(y2+x2)KQdx.y2+x2y=LKλy∫−2L2L(y2+x2)3/2dx

=Kλy[y2y2+x2

Explanation:

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