Find the electric field at the centre of a uniformly charged semi-circular arc of radius 'a' and linear charge density lambda.
Answers
Answered by
2
Answer:
The electric field due to the small length of the semicircle is given as
E=
4πε
0
R
2
dq
E=
4πε
0
R
2
λ.πR
By solving the above equation we get
E=
4ε
0
R
λ
Answered by
1
The electric field due to the small length of the semicircle is given as
E=
4πε
0
R
2
dq
E=
4πε
0
R
2
λ.πR
By solving the above equation we get
E=
4ε
0
R
λ
hope this helps you
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