Question

Find the electric field due to similar charged continuous plain sheet. How is it related to distance?​

Answer 1

Electrostatic Field Intensity due to charged sheet :

• We shall use Gauss' Law to find out the expression.

• Consider a cylindrical Gaussian surface coming out of the sheet.

• We will consider the sheet to be infinitely large, such that the field vector will be directed outwards.

$\displaystyle \therefore \: 2 \oint \vec{E}. \vec{ds} = \dfrac{q}{ \epsilon_{0}}$

$\displaystyle \implies\: 2 \oint E \times ds \times \cos( {0}^{ \circ} ) = \dfrac{q}{ \epsilon_{0}}$

$\displaystyle \implies\: 2 \oint E \times ds = \dfrac{q}{ \epsilon_{0}}$

$\displaystyle \implies\: 2 E \oint ds = \dfrac{q}{ \epsilon_{0}}$

$\displaystyle \implies\: 2 E s = \dfrac{q}{ \epsilon_{0}}$

$\displaystyle \implies\:E = \dfrac{q}{ 2s \epsilon_{0}}$

$\displaystyle \implies\:E = \dfrac{( \frac{q}{s} )}{ 2\epsilon_{0}}$

$\boxed{ \displaystyle \implies\:E = \dfrac{ \sigma}{ 2\epsilon_{0}} }$

Answer 2

if comb is rubbed on dry air it attracts pieces of paper