Question

Find the electric field intensity due to a charge of 6 micro coulomb find the electric field intensity at distance 100 cm

Answer 1

Given ,

• Charge (q) = 6 micro C or 6 × (10)^(-6) C
• Distance (r) = 100 cm or 0.1 m

We know that ,

The electric field at point a due to point charge is given by

$\large \boxed{ \sf{E = k \frac{q}{ {(r)}^{2} } }}$

Thus ,

$\sf \mapsto E = \frac{9 \times {(10)}^{9} \times6 \times {(10)}^{ - 6} }{ {(10)}^{ - 1} } \\ \\ \sf \mapsto E = 5.4 \times {(10)}^{5} \: \: N/c$

$\sf{ \therefore{\underline{The \: electri c \: field \: is \: 5.4 \times {(10)}^{ 5} \: N {c}^{ - 1} }}}$