Question

Find the electric field intensity due to a charge of 6 micro coulomb find the electric field intensity at distance 100 cm

Answer 1

Answer:

Explanation:

E = Kq/d²

= 9 × 10⁹ × 6 × 10⁶/ (100 × 10⁻²)²

= 54 × 10¹⁵N/C

K = const.= 9 × 10⁹

q = 6μC = 6 × 10⁶ C

Answer 2

Answer:

F=qE

where F= force experienced by two point charges

q=point charge

E=electric field

again from coulombs law we get

F= k.q²/r²

so...

k. q²/r²=qE

E=kq/r²

now the calculations are given in the attachment..

if you have any confusion now ask me again...