Question

find the electric field intensity of a point charge 2 UC at a distance of 10 cm in air​

Answer 1

Answer:

let thee charge is placed at distance x from 2Πc

Now the net force acting on charge Q should be zero .

$(10 - x)2k(1 \times 10 - 6)q = x2(2 \times 10 - 6)q \\ 10 - x1 = x2 \\ x = 102 - x2 \\ x(1 + 2) = 102 \\ x = 1 +2102 \\ x = 2.41414.14 \\ x = 5.857 \: cm$