Question

find the electric field of the 1/4pieo
in to fraction

Answer 1

Answer:

1/4 pi e0

Explanation:

Answer 2

Answer:

Hmm. Good question. Well, practically it's just the proportionality coefficient k in the Coulomb’s law: E(r)=14πε0qr2 = kqr2 , where ε0 is the .

There is an old interpretation of it but don't take it too seriously, because it's not entirely correct. So, here it goes: the electric field strength E(r) of an electric charge q at a distant r is given by (just rewrite it as) E(r)=(q/ε0)/A(r) , where A(r)=4πr2 is the surface area of the sphere of radius r centered at the location of the electric charge q . Now, when you rewrite it like this, the electric field strength E(r) can be interpreted as the local density of electric field lines (i.e. electric flux) at that point, that is total number of lines per unit area ∼(q/ε0)/A(r) . (This is the reason why in old texts electric field strength is also refereed as electric filed density.)

So in that sense q/ε0 is basically the total number of electric field lines (or, electric flux) emerging from a point electric charge q . Clearly, this number is finite and we know that electric field lines is not a physical concept but rather a geometric construct invented to explain the relative strengths of electric charges and their electric field strengths. Therefore, it must be taken with a pinch of salt.

Thus, according to this interpretation, one can say that 1/ε0 is the total number of electric field lines (or, electric flux) emanating from a unit electric charge. Also, note that it’s the inverse of the vacuum permittivity.

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