Question

find the electric flus through of 2m^2 an electric field of 200 h/m the angle between electric field and normal area is 60°​

Answer 1

Answer:

By definition, the flux of the constant field throug some area is:

\Phi =ES\cos \thetaΦ=EScosθ

where E = 200V/mE=200V/m is the electric field, S = 2m^2S=2m2 is the area, and \theta = 60\degreeθ=60° is the angle between electric field and normal to area. Thus, obtain:

\Phi = 200\cdot 2\cdot \cos 60\degree = 200V\cdot mΦ=200⋅2⋅cos60°=200V⋅m

Answer. 200 V*m. As the same answer