Question

find
the electric fluse through area
of
2 m²
in electric field of 200 v/m. The
angle between electric field and normal to area
is 60° .
​

Answer 1

Answer:

By definition, the flux of the constant field throug some area is:

\Phi =ES\cos \thetaΦ=EScosθ

where E = 200V/mE=200V/m is the electric field, S = 2m^2S=2m

2

is the area, and \theta = 60\degreeθ=60° is the angle between electric field and normal to area. Thus, obtain:

\Phi = 200\cdot 2\cdot \cos 60\degree = 200V\cdot mΦ=200⋅2⋅cos60°=200V⋅m

Answer. 200 V*m.