Question

Find the electronic field intensity in which a proton experience a force equal to its own weight

Answer 1

weight of 1 e- = mg

= 9 × 10^-31 × 10

= 9 × 10^-30

We know force F=Eq

Eq = 9 × 10^-30

=> E = (9 × 10^-30)/ (1.6×10^-19)

⇒E = (5⋅62×10^−11) N/C.