find the electrostatic and gravitational force between electron and proton that are placed 10 m apart
Answers
Explanation:
Compute the ratio of gravitational force and electrostatic force between an electron (mass- 9.1 × 10^-19 kg )and a proton (mass- . 1.7×10^-27 kg). GIVEN: e=1.6 ×10^-19C. G=6.67 ×10^-11 N m^2 /kg^-2. ANSWER GIVEN: 4.5 × 10^-40.
Answer:
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Explanation:
COULOMB’S LAW
F
=
k
∣
q
1
q
2
∣
r
2
Coulomb’s law calculates the magnitude of the force F between two point charges, q1 and q2, separated by a distance r. In SI units, the constant k is equal to
k
=
8.988
×
10
9
N
⋅
m
2
C
2
≈
8.99
×
10
9
N
⋅
m
2
C
2
The electrostatic force is a vector quantity and is expressed in units of newtons. The force is understood to be along the line joining the two charges. (See Figure 2).
Although the formula for Coulomb’s law is simple, it was no mean task to prove it. The experiments Coulomb did, with the primitive equipment then available, were difficult. Modern experiments have verified Coulomb’s law to great precision. For example, it has been shown that the force is inversely proportional to distance between two objects squared
(
F
∝
1
r
2
)
to an accuracy of 1 part in 1016. No exceptions have ever been found, even at the small distances within the atom.
In part a, two charges q one and q two are shown at a distance r. Force vector arrow F one two points toward left and acts on q one. Force vector arrow F two one points toward right and acts on q two. Both forces act in opposite directions and are represented by arrows of same length. In part b, two charges q one and q two are shown at a distance r. Force vector arrow F one two points toward right and acts on q one. Force vector arrow F two one points toward left and acts on q two. Both forces act toward each other and are represented by arrows of same length.