Question

find the electrostatic force between +1 c and +3 c by a distance of 1 metre.

Answer 1

hey... here's ur solution !!

F = kq 1 q2/ r²

9× 10 took power 9 ×1×3. / (1) ²

F = 27 × 10 took power 9 N.


hope it might be helpful !!

Answer 2

The electrostatic force beyween 2 charged body is defined by
K(q1 × q2 ) / (r^2).


Where q1 and q2 are the 2 charges and r is the distance between them.
and K is a constant which equals 9×10^9 Nm^2/C^2

In this question, by appling this columb's law
the electrostatic force equals

$\frac{3 \times 1 \times 9 \times {10}^{9} }{ {1}^{2} } \\ = 27 \times {10}^{9}$

Therefore,
the electrostatic force in this case equals 27 ×10^9 C.