Question

find the electrostatic force between two protons separated by a distance 20 cm

Answer 1

Putting the value of q1 and q2 as 1.6 * 10(-19) C as it is the charge on both protons, r as 20/100 m = 0.2 m and k as 9 * 109 Nm/C2

Therefore,
F = 9 * 109 * (1.6 * 10-19)2 / (0.2)2
F = 9 * 109 *  2.56 * 10-38 / 0.04
F = 9 * 64 * 10-31
F = 576 * 10-31
F = 5.76 * 10-29 N

Answer 2

5.76 x 10-27N


Answer