find the elevation of sun when 5m. pole cast a shadow of lenght of 5 m
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Answered by
5
Answer:
Let the angle of elevation be
′
θ
′
.
In, △ACB,
⇒tanθ=
BC
AB
=
5
5
3
⇒tanθ=
3
⇒ Or θ=60
∘
Step-by-step explanation:
hence the angle will ne 60*
Answered by
2
Here, let ABC be a ∆ in which AB is the side (5m long), CB is the shadow cast by the pole (5m long) and angle B is a right angle.
_______________________________________
So, height of pole/length of shadow cast
= AB/CB
= 1
_______________________________________
We know that,
tan 45° = 1
This implies that,
The angle of elevation of sun is 45°.
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Hope it helps uh :)
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