Question

Find the eleventh term from the last term of the AP: 27, 23, 19, ..., –65.

Answer 1

Let the first term of AP be 'a'
i.e a=27
Let the common difference between two consecutive terms of an AP be 'd'
i.e d= 23-27 = -4
Let the last term(nth term) be tn
i.e tn=-65
Acoording to the formula,
tn= a+(n-1)*d
=> -65=27+(n-1)(-4)
=> -65=27-4n+4
=> 4n=27+4+65
=> 4n=96
=> n=24
n denotes the number of terms in AP
Now let us find 11th term
t11=27+(11-1)(-4)
t11=27-40
t11= -13
The answer is -13
Hope it helps.

Answer 2

#helpingismypleasure

hope it helps you

answer is (-25)