find the elongation of wire having cross sectional area of 0.5 cm^2, if 9 N force is applied
Answers
Answered by
2
Explanation:
Given,
l
Δl
×100=0.1%
l
Δl
=
100
0.1
=1×10
−3
Cross-sectional area, A=10
−6
m
2
T=100N
Young's modulus,
Y=
Δl/l
T/A
=
10
−3
100/10
−6
=
10
−9
100
Y=10
11
N/m
2
Answered by
2
Answer:
this is a correct answer uska wrong hai
Explanation:
Given,
l
Δl
×100=0.1%
l
Δl
=
100
0.1
=1×10
−3
Cross-sectional area, A=10
−6
m
2
T=100N
Young's modulus,
Y=
Δl/l
T/A
=
10
−3
100/10
−6
=
10
−9
100
Y=10
11
N/m
2
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