Question

Find the Emperical Formula and molecular formula if;
B=86.64 %
H = 13.36%
molecular weight=46
(H=1; B=11)​

Answer 1

Answer:

Steps

1 Find the empirical formula of a compound that has 86.64% of Boron (B), 13.36% of Hydrogen (H).

2 Find molar mass of each component: B=10.811, H=1.00794

3 Convert to moles: B=8.0140597539543, H=13.254757227613

4 Find smallest mole value: 8.0140597539543

5 Divide all components my smallest value: B=1, H=1.6539379084455

6 Divide by fractional component of each mole value: B=1.5291971716047, H=2.5291971716047

7 Round to closest whole numbers: B=2, H=3

8 Combine to get the empirical formula: B2H3