Question

find the empirical and molecular formula for the compound which contains 51.28%of carbon,9.40% of hydrogen 27.35% of oxygen and 11.97%g nitrogen molar mass of the compound is 234g/mol

Answer 1

Answer:

Here is the correct answer

Explanation:

Divide all the percentages with atomic mass,

Carbon 49.2

12

49.2

=4.1 3

Hydrogen 9.68

1

9.68

=9.68 9

Nitrogen 19.9

14

19.9

=1.4 1

Oxygen 21.22

16

21.22

=1.3 1

Empirical formula will be C

3

H

9

NO

(Emperical formula wt)

n

=146

(75)

n

=146 or n=2,

Molecular will be C

6

H

18

N

2

O

2