Find the empirical formula for a compound containing 40.6% carbon, 5.1% hydrogen, and 54.2% oxygen.
Answers
Explanation:
To find the ratio in moles you divide by the [A] of each element.
Using approximate values:
Ratio in grams C:H:O ⇒ 40.6 : 5.1 : 54.2
Ratio in moles ⇒ 40.6/12 : 5.1/1 : 54.2/16
3.38 : 5.1 : 3.38
⇒ [Divide each mole value by the smallest number of moles calculated. Round to the nearest whole number. ]
3.38 / 3.38 : 5.1 / 3.38 : 3.38 / 3.38 [Dividing through by 3.38]
1: 1.5 : 1
[ If the number is too far to round (x.1 ~ x.9), then multiply each solution by the same factor to get the lowest whole number multiple.]
1* 2 : 1.5 *2 : 1 *2 [multiply through by 2]
2 : 3 : 2
So the empirical formula is: C2H3O2 ANS
IUPAC Name acetate
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